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Lady Luck: Jackpot Joan Scoops Fourth Win
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Author:  pcernie [ Tue Jul 06, 2010 12:24 pm ]
Post subject:  Lady Luck: Jackpot Joan Scoops Fourth Win

http://news.sky.com/skynews/Home/Strang ... 0165?f=rss

Erm, time for an investigation I think :shock: :lol:

Author:  big_D [ Tue Jul 06, 2010 1:12 pm ]
Post subject:  Re: Lady Luck: Jackpot Joan Scoops Fourth Win

Quote:
With the odds of four multi-million-pound wins at over 200 million to one, it is no surprise the 63-year-old, who lives in Las Vegas, Nevada, has been dubbed the jammiest person alive.

The chances of winning a fourth time are exactly the same as winning for the first time, it isn't cumulative odds.

Author:  rustybucket [ Tue Jul 06, 2010 1:43 pm ]
Post subject:  Re: Lady Luck: Jackpot Joan Scoops Fourth Win

big_D wrote:
Quote:
With the odds of four multi-million-pound wins at over 200 million to one, it is no surprise the 63-year-old, who lives in Las Vegas, Nevada, has been dubbed the jammiest person alive.

The chances of winning a fourth time are exactly the same as winning for the first time, it isn't cumulative odds.

Yes - and no.

Once you have won 3 times, the probability of the fourth win is the same as that of the first.

However, the probability of winning a first time AND and a second time AND and a third time AND and a fourth time is:

P (4xwin) = (P (win)) AND (P (win)) AND (P (win)) AND (P (win))
P (4xwin) = (P (win)) * (P (win)) * (P (win)) * (P (win))
P (4xwin) = (P (win)) ^ 4

Which means that they've got their sums wrong - by their reckoning, the odds of a single win are 119/1. I want to enter that lottery!

The odds of a single win for the Texas State Lottery are stated as 25,867,165 / 1. This means that the odds of a quadruple win are actually (4.47708493383 x 10^29) / 1.

Time to investigate I think.

Author:  Amnesia10 [ Tue Jul 06, 2010 4:11 pm ]
Post subject:  Re: Lady Luck: Jackpot Joan Scoops Fourth Win

She is clearly from the future and is trying to win enough money to build her own time machine to get back home.

Author:  eddie543 [ Wed Jul 07, 2010 1:29 am ]
Post subject:  Re: Lady Luck: Jackpot Joan Scoops Fourth Win

watch out to see if she is mysteriously ravaged in a "dog" attack. Which is infact a hellhound.

Author:  Alexgadgetman [ Wed Jul 07, 2010 1:54 pm ]
Post subject:  Re: Lady Luck: Jackpot Joan Scoops Fourth Win

Quote:
P (4xwin) = (P (win)) AND (P (win)) AND (P (win)) AND (P (win))
P (4xwin) = (P (win)) * (P (win)) * (P (win)) * (P (win))
P (4xwin) = (P (win)) ^ 4

Which means that they've got their sums wrong - by their reckoning, the odds of a single win are 119/1. I want to enter that lottery!

The odds of a single win for the Texas State Lottery are stated as 25,867,165 / 1. This means that the odds of a quadruple win are actually (4.47708493383 x 10^29) / 1.

Time to investigate I think.


Yet the probability of a quadruple win will also depend upon how many tickets she has bought...
Seeing as I dont actually have a clue how these scratchcards work (chances are a £1.3million win are higher than a £6.6million win). Although obviously the odds arent cumulative they will still vary after numberous scratchcards.
Say there is a 0.1 chance of winning something, each time it is independant probability of the last.
So on the first time the probability of a loss is 9/10
The second time the probability of a loss is 9/10
The third time the probability of a loss is 9/10
and so on and so on.

So say you buy 50 scratchcards the probability of losing every time is 9/10 to the power of 50.

So in the instance of her buying these scratchcards, the more she bought, the more likely she should be to have a win. Which is why i think the value of:

Quote:
This means that the odds of a quadruple win are actually (4.47708493383 x 10^29) / 1.


Is probably a much too low probability.

Anyway, you will hopefully get where this is aimed (it isnt actually suggesting the earlier P working was in any way wrong, just didnt consider all her fails.

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